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The Constant-Total Method

A transfer changes the parts, but the whole stays the same.

⏱ 5 min · 🎯 4 things to master

Constant Total Explained with Bar Models | Singapore Primary Maths

Video · 4:33

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When something moves from one person to another, the two amounts change but their combined total stays constant. This method keeps the whole visible. Think of a fixed tray of counters: moving counters between two boxes changes the split, never the whole tray.

Parents: ask your child to write the total before and after the transfer. If the transfer stays inside the two people, both totals must match.

By the end, you will be able to spot an internal transfer, find one unit from the change, and check the total before and after.

Keep the whole fixed

An internal transfer has opposite changes: one amount loses what the other gains. A gift from outside, a purchase, or a loss does change the combined total, so use a BCA table to record it first.

🤔 Predict first: Sam gives $12 to Priya. What happens to their combined amount?

Equalise by moving one unit

Priya and Sam have money in the ratio 3 : 5. Sam gives Priya $12, and they then have equal amounts. Find their starting amounts.

After the transfer the eight units are split equally into four units and four units. Priya gains one unit, so one unit is twelve dollars. The original bars are three units and five units.

Two bars in ratio three to five exchange one unit to become four units each while the eight-unit total stays fixed.
The transfer makes the bars equal without changing their combined eight units.

Move the transfer

Predict first: After an internal transfer, what must happen to the combined total?

Find one unit

3+5=8 units3+5=8\text{ units}
After equal: 8÷2=4 units each\text{After equal: }8\div2=4\text{ units each}
4−3=1 unit=$124-3=1\text{ unit}=\$12
Priya before=3×12=$36\text{Priya before}=3\times12=\$36
Sam before=5×12=$60\text{Sam before}=5\times12=\$60
Priya after=36+12=48\text{Priya after}=36+12=48
Sam after=60−12=48\text{Sam after}=60-12=48

The total check is twelve dollars transferred within the pair: the starting total and final total are both ninety-six dollars.

Do not confuse constant total and constant part

Constant total describes a transfer between two quantities. Constant part describes a piece that stays unchanged while another piece changes. If the question says a fixed number is removed from each amount, compare the unchanged piece; if it says one amount is given to the other, keep the total fixed.

Practice: transfer inside the pair

1. Red and blue counters are in the ratio 2 : 6. Twelve blue counters move to red, and the amounts become equal. Find the starting amounts and the final amount in each group.

Working

After equal: (2+6)÷2=4 units each\text{After equal: }(2+6)\div2=4\text{ units each}
4−2=2 units=12 counters4-2=2\text{ units}=12\text{ counters}
1 unit=12÷2=6 counters1\text{ unit}=12\div2=6\text{ counters}
Red start=2×6=12\text{Red start}=2\times6=12
Blue start=6×6=36\text{Blue start}=6\times6=36
Red after=12+12=24\text{Red after}=12+12=24
Blue after=36−12=24\text{Blue after}=36-12=24
2. Mo and Lin have money in the ratio 1 : 3. Mo receives $18 from Lin and they become equal. Find their starting amounts.

Working

After equal: (1+3)÷2=2 units each\text{After equal: }(1+3)\div2=2\text{ units each}
2−1=1 unit=$182-1=1\text{ unit}=\$18
Mo before=1×18=$18\text{Mo before}=1\times18=\$18
Lin before=3×18=$54\text{Lin before}=3\times18=\$54
Mo after=18+18=36\text{Mo after}=18+18=36
Lin after=54−18=36\text{Lin after}=54-18=36
3. Two sticker collections are in the ratio 3 : 7. Nine stickers move from the larger collection to the smaller. The new ratio is 4 : 6. Find the original piles.

Working

Total=3+7=10 units\text{Total}=3+7=10\text{ units}
Moved=9=1 unit\text{Moved}=9=1\text{ unit}
After smaller=3+1=4 units\text{After smaller}=3+1=4\text{ units}
After larger=7−1=6 units\text{After larger}=7-1=6\text{ units}
One unit=9 stickers\text{One unit}=9\text{ stickers}
Original smaller=3×9=27\text{Original smaller}=3\times9=27
Original larger=7×9=63\text{Original larger}=7\times9=63
After amounts=36 and 54\text{After amounts}=36\text{ and }54

Watch out — easily mixed up

Quick recap

🎯 Mastery check

Answer all 6 — your progress is saved on this device.

  1. Sam gives money to Priya from his own amount. What happens to their combined total?

  2. A ratio is 3 : 5 and an internal transfer makes it 4 : 4. How many units move into the smaller part?

  3. If one transferred unit is worth $12, what is a starting part of three units worth?

  4. Which change can make the combined total change?

  5. What should the before and after totals do in a constant-total problem?

  6. What is the safest first step when a transfer is described?

Ready to keep the whole steady? Follow the transfer from one part to the other and let the unchanged total anchor your model.