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The Remainder Model

How to name the parent whole for each fraction, re-cut a remainder into equal units, and solve two-stage fraction problems.

⏱ 9 min · 🎯 4 things to master

Which Whole? Fractions of a Remainder Explained | Primary Maths

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The word remainder changes the parent of a fraction. If 25\frac{2}{5} of the books on a trolley are storybooks, then 13\frac{1}{3} of the remaining books are comics, that 13\frac{1}{3} is not cut from all the books. It is cut from the leftover 35\frac{3}{5}. Name each whole before you calculate and the model stays honest.

Parents: ask your child to point to the parent whole for each fraction and predict the next cut before revealing the worked model.

By the end you will be able to identify each fraction's parent whole, enlarge the remainder without changing its amount, and solve a two-stage remainder problem.

Name the parent whole

A is the amount the fraction is talking about. In “25\frac{2}{5} of all the books”, the parent is the entire trolley. In “13\frac{1}{3} of the remaining books”, the parent is only the books left after storybooks are set aside.

The is still part of the original whole, but it can become a new parent for the next fraction. That is the key move.

🤔 Predict first: 25\frac{2}{5} of a trolley are storybooks. 13\frac{1}{3} of the remaining books are comics. The 13\frac{1}{3} is taken from…

Cut the original bar, then re-cut the leftover

Work through this trolley problem:

25\frac{2}{5} of the books on a trolley are storybooks. 13\frac{1}{3} of the remaining books are comics. The rest are information books. There are 48 information books. How many books are on the trolley?

First cut all books into 5 equal shares. Storybooks take 2 shares, leaving a remainder of 3 shares. Now look only at those 3 remainder shares. 13\frac{1}{3} of them is 1 share of comics, leaving 2 shares of information books.

The diagram below enlarges the three-share remainder so that its inner cut is easy to see. The enlargement is a focus view: it does not create more books.

Nested trolley-book model with a five-share whole, a three-share remainder, and an enlarged remainder split into one comic share and two information shares labelled 48 books.
The enlarged three-share bar is the same remainder, re-cut so the one comic share and two information shares are clear.

The information books occupy 2 original shares. Use the known information count to value a share, then read the five-share original bar.

Find the whole trolley

2 shares=48 books2\text{ shares} = 48\text{ books}
1 share=48÷2=24 books1\text{ share} = 48 \div 2 = 24\text{ books}
Whole trolley=5×24=120 books\text{Whole trolley} = 5 \times 24 = 120\text{ books}

🤔 Predict first: If the remainder has 3 equal shares and 13\frac{1}{3} is comics, how many remainder shares are information books?

Re-cut into one common small unit

The two cuts can be combined into one exact grid. Five original shares, each split into three small pieces, make 15 equal small units. In that grid:

Make equal small units

Storybooks=2×3=6 small units\text{Storybooks} = 2 \times 3 = 6\text{ small units}
Comics=1×3=3 small units\text{Comics} = 1 \times 3 = 3\text{ small units}
Information=2×3=6 small units\text{Information} = 2 \times 3 = 6\text{ small units}
Whole trolley=5×3=15 small units\text{Whole trolley} = 5 \times 3 = 15\text{ small units}

The 48 information books fill 6 small units. The re-cut makes each piece comparable without changing the number of books.

Value the small unit

1 small unit=48÷6=8 books1\text{ small unit} = 48 \div 6 = 8\text{ books}
Whole trolley=15×8=120 books\text{Whole trolley} = 15 \times 8 = 120\text{ books}

Use the adjustable experiment below. Predict which part is the parent, then step the value of one small unit until the information section matches 48.

Trolley books: re-cut the remainder

Predict first: After 25\frac{2}{5} are storybooks, the 13\frac{1}{3} applies to which parent?

🤔 Predict first: In the 15-unit grid, information books occupy 6 units and total 48. What is one small unit?

Check the whole before you add fractions

The nested model gives a clean check:

Check each parent whole

25×120=48 storybooks\frac{2}{5} \times 120 = 48\text{ storybooks}
Remainder=120−48=72 books\text{Remainder} = 120 - 48 = 72\text{ books}
13×72=24 comics\frac{1}{3} \times 72 = 24\text{ comics}
Information=72−24=48 books\text{Information} = 72 - 24 = 48\text{ books}

The categories add to 48 + 24 + 48 = 120. Notice that 13\frac{1}{3} of the original 120 would be 40, but comics are 24 because the fraction was taken from the smaller remainder of 72.

🤔 Predict first: A tank is 12\frac{1}{2} full. Then 23\frac{2}{3} of the water is used. What fraction of the full tank was used in the second step?

Watch out — easily mixed up

Quick recap

Graduated practice

These move from naming the parent to handling two fractions that share the original whole. Open each solution only after you have named its parent whole.

1. Art books and biographies

14\frac{1}{4} of a shelf is art books. 23\frac{2}{3} of the remaining books are biographies. The final 18 books are atlases. How many books are on the shelf?

Show solution

Use 12 original shares. Art uses 3, leaving 9. Biographies use 6 of those 9, leaving 3 shares for atlases.

Practice 1

3 shares=18 atlases3\text{ shares} = 18\text{ atlases}
1 share=18÷3=6 books1\text{ share} = 18 \div 3 = 6\text{ books}
Shelf=12×6=72 books\text{Shelf} = 12 \times 6 = 72\text{ books}

Check: 18 art, 36 biographies, 18 atlases.

2. Beads left after yellow

27\frac{2}{7} of 84 beads are yellow. 13\frac{1}{3} of the remainder are blue. How many beads are neither yellow nor blue?

Show solution

Yellow beads are 27\frac{2}{7} of 84. Then calculate the second fraction from the remainder.

Practice 2

27×84=24 yellow beads\frac{2}{7} \times 84 = 24\text{ yellow beads}
Remainder=84−24=60 beads\text{Remainder} = 84 - 24 = 60\text{ beads}
13×60=20 blue beads\frac{1}{3} \times 60 = 20\text{ blue beads}
Neither=60−20=40 beads\text{Neither} = 60 - 20 = 40\text{ beads}

3. Two parts of the same total

310\frac{3}{10} of 90 cards are red and 25\frac{2}{5} of the same 90 cards are blue. The rest are green. How many are green?

Show solution

Both fractions name the original 90 cards, so neither fraction is taken from a remainder.

Practice 3

310×90=27 red cards\frac{3}{10} \times 90 = 27\text{ red cards}
25×90=36 blue cards\frac{2}{5} \times 90 = 36\text{ blue cards}
Green=90−27−36=27 cards\text{Green} = 90 - 27 - 36 = 27\text{ cards}

The words “the same 90 cards” keep both fractions on the original parent whole.

🎯 Mastery check

Answer all 7 — your progress is saved on this device.

  1. Ben read 13\frac{1}{3} of a book, then 12\frac{1}{2} of the remainder the next day. The 12\frac{1}{2} applies to…

  2. After spending 25\frac{2}{5} of some money, what fraction is left as the remainder?

  3. A bar is split into 5 shares and each share is re-cut into 3 equal small units. How many units make the whole bar?

  4. A boy spends 12\frac{1}{2} of his money, then 14\frac{1}{4} of the remainder. What fraction of the original money is the second amount?

  5. In a remainder model, 6 equal small units carry 48 information books. What is one unit?

  6. Why is 25\frac{2}{5} + 13\frac{1}{3} wrong for the trolley problem?

  7. A shelf has 12 original shares. The final atlas part is 3 shares and equals 18 books. What is the total shelf size?